Math, asked by missbrains4436, 1 year ago

Find the value of (i) cos22°/sin68° (ii) tan47°/cot43° (iii) sec75°/cosec15°

Answers

Answered by evaninan
1
i) cos 22°/sin 68°
= sin (90°-22°)/sin 68°
=sin 68°/ sin 68°
=1

ii) tan 47°/cot 43°
= cot(90°-47°)/cot 43°
=cot 43°/cot 43°
= 1

iii) sec 75° /cosec 15°
=cosec (90°-75°)/cosec 15°
=cosec 15° / cosec 15°
= 1
Answered by santoshauti1111
0

Answer:

i) cos 22°/sin 68° = sin (90°-22°)/sin 68° =sin 68°/ sin 68°

=1

ii) tan 47°/cot 43° = cot(90°-47°)/cot 43° =cot 43/cot 43° = 1

iii) sec 75° /cosec 15°

=cosec (90°-75°)/cosec 15° =cosec 15° / cosec 15° = 1

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