Find the value of
I) cos480° ii) sin1230°
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I) cos480° = cos (360° + 120° )
= Cos120°
= cos ( 180° -- 60° ) = -60°
= - 1/2
ii) sin1230° = sin(3×360°+150° )
= sin150°
= Sin ( 180° -- 30° ) = Sin30°
= 1/2.
= Cos120°
= cos ( 180° -- 60° ) = -60°
= - 1/2
ii) sin1230° = sin(3×360°+150° )
= sin150°
= Sin ( 180° -- 30° ) = Sin30°
= 1/2.
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TRIGONOMETRIC FUNCTIONS
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