find the value of √i+√-i
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i=(e^Π/2)
√i=i^(1/2)=(e^Π/2)^1/2
=(e^Π/4)
=cos(Π/4)+ i sin(Π/4)
=1/√2+i/√2
Similarly,
√-i=i^(1/2)=(e^Π/2)^(-1/2)
=cos(Π/4)- i sin(Π/4)
=1/√2-i/√2
Adding them,
=2/√2=√2
Step-by-step explanation:
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