Math, asked by tejaskhokale05, 5 months ago

find the value of :-
(i) tan 30° tan 60°
(ii) sin² 30°+cos²30+cot²45°
(iii)cos² 60° + sin² 30°​

Answers

Answered by veerarajuch1114
1

Step-by-step explanation:

(1)1+3/√3

(2) 2

(3) 1/2

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Answered by kushalchauhan07
2

Answer:

(i) \: tan30 \degree \: tan60 \degree

∴ \:  \: tan30 \degree \:  =  \sqrt{3}  \:  \:,</p><p> tan60 \degree \:  =  \frac{1}{ \sqrt{3} }

 =  \sqrt{3}  \times  \frac{1}{ \sqrt{3} }  = 1

(ii) \: sin^{2} 30 \degree +  {cos}^{2} 30 \degree +  {cot}^{2}45 \degree

∴ (\: sin^{2} 30 \degree +  {cos}^{2} 30 \degree = 1)

∴cot 45 \degree = 1

 = 1 \times 1 = 1

(iii) \: cos^{2}  60 \degree +  {sin}^{2}30 \degree

 ∴cos60 \:  =  \frac{1}{2} ,</p><p></p><p></p><p>sin30 =  \frac{1}{3}

 ( \frac{1}{2}) ^{2}+( \frac{1}{2})^{2} =  \frac{1}{4} +  \frac{1}{4}  =  \frac{2}{4}  =  \frac{1}{2}

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