Question

find the value of I , those are 1 Q which are not visible properly ​

Answer 1

Answer:

hi there , I will show how to solve this questions

Explanation:

Given = potential difference,V =5

two resistors say R1 and R2 are in series=

2 and 1 ohm respectively

again, two resistors are in series say R3

and R4 respectively= 2 and 1 ohm

Now,

For first two resistors, R1 and R2= R1+R2=2+1=3 ohm

Again,

For second two resistors, R3 and R4=2+1=3 ohm

Now, we have two resistors which are formed by using R1, R2, R3, and R4 resistors,

Using parallel combination ,

1/R=1/R1+1/R2+1/R3+1/R4

= 1/3+1/3

=2/3

Now, using ohm's Law

V=IR

5=I x 2/3

I= 5*3/2

=15/2 Ampere