Question

Find the value of i1/i2 in the figure (32-E3) if (a) R = 0.1 Ω (b) R = 1 Ω and (c) R = 10 Ω. Note from your answers that in order to get more current from a combination of two batteries, they should be joined in parallel if the external resistance is small and in series if the external resistance is large, compared to the internal resistance.
Figure 32-E3

Answer 1

Answer:

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Answer 2

(a) Value of i1/i2 = 0 if R= 0.1 Ω

(b) Value of i1/i2 = ½ when R = 1 Ω

(c)  Value of i1/i2 = 0 when R = 10 Ω

Explanation:

a) I1 = 12/2.1

⇒ i-6+6 – (i2-i1) =0

⇒ 2i-i2 =0 ⇒-2i+0.2i=0

⇒i2=0.

b) 1i1 + 1 i1-6+1i1 = 0

⇒3i1 = i2 =4

⇒I2+ (i2-i)-6=0

⇒i2=8

I1/i2 = 4/8=1/2

C)  ⇒10i1+1i1-6+1i1-6=0

⇒10i2-i1-6=0

⇒11i2 =6

Therefore, it can be seen that -i2=0