Question

find the value of i¹⁸+i¹⁹+i²⁰+i²¹

Answer 1

Answer:

hhhhiiiiii jsjsjsnsbwj

Step-by-step explanation:

jhhzjskwwnsvsjjssksjs

Answer 2

Answer:

Sum of four consecutive terms in complex series is always zero.

let me show you how.

Step-by-step explanation:

When you try to write the powers then make sure that you'll make it in the multiple of 4 because

>> i^4 = 1

So method to write the powers is as follows.

Step 1 :- Divide the power by 4 or any number corresponding to the values of powers 1 , 2 , 3

or 4

so for sake of convenience, I've taken i^4 because its value is 1 so we can easily relate with that.

Step 2:- After division the smallest number or we can say remainder which is left after division is taken and lets say we got 2 then we write it as

> For eg.

>> i^2 = -1

So not making it lengthier , I'll move forward to

this question.

Then,

>i^18 = i^2 = -1 {after division of 18 by 4

remainder is 2}

>i^19 = i^3 = -i {after division of 19 by 4

remainder is 3}

>i^20 = i^0 = 1 {after division of 20 by 4

remainder is 0}

>i^21 = i^1 = i {after division of 21 by 4

remainder is 1}

Therefore,

when you add all these values, answer comes out to be 0.

> i^18 + i^19 + i^20 + i^21

> (-1) + (-i) + (1) + (1)

> 0

Hence , it is applicable to atmost all the cases.

I HOPE IT HELPS.