English, asked by sivascs864123, 5 hours ago

Find the value of (i2+1) (i2+2) (i2+3)... (i+n).​

Answers

Answered by dalyby86
1

Answer:

We know that (a−b)

2

=a

2

+b

2

−2ab So

(2−3i)

2

=2

2

+(3i)

2

−2×2×3i=4+9i

2

−12i

And i is an imaginary number whose value is

−1

So, i

2

=−1

⇒4+9i

2

−6i=4−9−12i=−5−12i

⇒(2−3i)

2

=−5−12i

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