Find the value of (i2+1) (i2+2) (i2+3)... (i+n).
Answers
Answered by
1
Answer:
We know that (a−b)
2
=a
2
+b
2
−2ab So
(2−3i)
2
=2
2
+(3i)
2
−2×2×3i=4+9i
2
−12i
And i is an imaginary number whose value is
−1
So, i
2
=−1
⇒4+9i
2
−6i=4−9−12i=−5−12i
⇒(2−3i)
2
=−5−12i
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