Find the value of i³⁵
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Answer:
i⁻³⁵
=i⁻³⁴⁻¹
=(i²)⁻¹⁷×(i⁻¹)
=(-1)⁻¹⁷(1/i)
=1/(-1)¹⁷(1/i)
=(-1)(1/i)
=-1/i
=0+i(-1/i²)
=0+i(-1/-1)
=0+i.1
where a=0, b=1
Step-by-step explanation:
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