Find the value of i⁴⁹+i⁶⁸+i⁸⁹+i¹¹⁰
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Answer:
i⁴⁹ + i⁶⁸ + i⁸⁹ + i¹¹⁰ = 2i
Solution:
∴ i⁴⁹ + i⁶⁸ + i⁸⁹ + i¹¹⁰
= i⁴⁸⁺¹ + i⁶⁸ + i⁸⁸⁺¹ + i¹¹⁰
= i⁴⁸.i + i⁶⁸ + i⁸⁸.i + i¹¹⁰
= (i²)²⁴.i + (i²)³⁴ + (i²)⁴⁴.i + (i²)⁵⁵
= (- 1)²⁴.i + (- 1)³⁴ + (- 1)⁴⁴.i + (- 1)⁵⁵
= 1.i + 1 + 1.i - 1
= i + 1 + i - 1
= 2i , which is the required value.
Now if we want to find the modulus value, we find the modulus value of 2i, which is given by
| 2i | = √(0² + 2²) = 2
Note:
Here i = √(- 1) and i² = - 1
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