Question

find the value of i49+ i68+i89+ i110​

Answer 1

Answer:

i^49+i^68+i^89+i^110=2i

Step-by-step explanation:

^ is sign for raised to

=i^49 + i^68+ i^89+i^110

=(i²)^24*i + (i⁴)^17+(1²)⁴⁴*i+(i²)^55

[ i²= -1 & i⁴=1]

substituting values of i²&i⁴

=(-1)²⁴*i+(1)^17 + (-1)⁴⁴*i+(-1)^55

=1*i+1+1*i-1

=i+i+1-1

=2i

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