Find the value of i49 +i68+i93+i110
a) -i b)-2i c)i d)2i.
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Answer:
2i
Step-by-step explanation:
i49 + i68 + i89 + i110 = i(48 + 1) + i68 + i(88 + 1) + i(108 + 2)
= (i4)12 × i + (i4)17 + (i4)11 × i + (i4)27 × i2
= i + 1 + i – 1 = 2i
[since i4 = 1, i2 = – 1]
i49 + i68 + i89 + i110 = 2i
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