find the value of in (2 + 3 i ) rah (2 - 3 i) solve by step wise
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Answered by
0
Step-by-step explanation:
(a+b) (a-b)=a²- b²
here a= 2
b= 3i
(2 + 3 i )(2 - 3 i)
= (2)² - (3i)²
= 4 - 9i²
we know that, i²= -1
therefore,
(2 + 3 i )(2 - 3 i) = 4+9
= 13
Answered by
0
Answer:
2^2- (3i)^2
4 - (3*-1)^2
4--3^2
4+9
=13
hint:i^2=-1
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