Math, asked by tajinderkaur4080, 11 months ago

Find the value of integral x/a^2cos^2x+b^2sin^2x

Answers

Answered by ankurkrishnamishra67
0

Answer:

Let I=∫(0→π) xdx/(a2cos2x+b2sin2x) ............(i) ....................(ii) Read more on Sarthaks.com - https://www.sarthaks.com/50596/evaluate-0-xdx-a-2cos-2x-b-2sin-2x

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