Math, asked by amanrjrj62, 1 year ago

find the value of integration ​

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Answered by kaushik05
49

Answer:

  \boxed{\bold{ i =  \frac{5}{6}  log(3 {x}^{2}  + 2x + 1)  -  \frac{11}{3 \sqrt{2} }  {tan}^{ - 1} ( \frac{3x + 1}{ \sqrt{2} } ) + c}}

For this type of question ,

 \int \:  \frac{px + q}{a {x}^{2}  + bx + c} dx \\

we Let ,

  \green\star \boxed{ \red{ \bold{ (px + q) = A \: (d.c \: of \: (a {x}^{2}  + bx + c)) +  B }}}

=> Here , Find the value of A and B by comparing the coefficients of X and constant term on both sides .

=> By this, question will reduce to sum of two integrals .

Formula used :

  \red \star \boxed{ \bold{ \int  \frac{1}{x} dx =  log(x)  + c}}

  \green\star \boxed{ \bold{ \int \:  \frac{1}{ {x}^{2} + a^{2}  } dx =  \frac{1}{a}  {tan}^{ - 1}  \frac{x}{a}  + c}} \\

Solution refer to the attachment

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Anonymous: Fantastic answer
kaushik05: thanks :)
Anonymous: Splendid, Awesome, Mind blowing , great , Fabulous, Fantastic , Marvelous ...
kaushik05: sukriya anku ♡
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