Question

Find the value of 'K'

Answer 1

in this case

discriminant will be equal to zero

here

b=-2(k-1)

a=1

c=1

b^2-4ac=0

4(k^2+1-2k)-4×1×1=0

4k^2+4-8k-4=0

4(k^2-2k)=0

4k(k-2)=0

k=0

k=2

both value will satisfy the ,condition of equal roots

Answer 2

Answer:

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Step-by-step explanation:

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