Find the value of k ×+2 is a factor of p(×) =kײ- 4× + 6k ?
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Answer:
x+k = 0
x = -k
x^4-k^2x^2+3x-6k = 0
(-k)^4-k^2(-k)^2+3(-k) -6(-k) = 0
k^4-k^4-3k+6k = 0
3k = 0
k = 0/3
k = 0
Hope it hlpz....
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