Math, asked by 2vasundhara176, 7 hours ago

Find the value of k (-2)^k+1 × (-2)^3 = (-2)^7

Answers

Answered by palgandhi757
1

Answer:

k=3

Step-by-step explanation:

(-2)^k+1×(-2)^3=(-2)^7

(-2)^k+1+3=(-2)^7

k+4=7

k=7-4=3

Answered by arpanaial06
2

Answer:

bases are same power should be added

 { (- 2)}^{k + 1}  × (-2)^3 = (-2)^7

 {( - 2)}^{k + 1 + 3}  =  {( - 2)}^{7}

corresponding side are equal

k + 1 + 3 = 7

k + 4 = 7

k = 7 - 4

k = 3

hope it will help you dear ☺️

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