Question

find the value of K 2x^2+Kx+3=0 have two equal roots​

Answer 1

Answer:

±2√6

Step-by-step explanation:

k²- 4.2.3=0

k²=24

k = ±2√6

Answer 2

EXPLANATION.

Quadratic equation.

⇒ 2x² + kx + 3 = 0.

As we know that,

D = Discriminant Or b² - 4ac.

For equal roots : D = 0.

⇒ (k)² - 4(2)(3) = 0.

⇒ k² - 24 = 0.

⇒ k² = 24.

⇒ k = √24.

⇒ k = ± 2√6.

                                                                                                                       

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.