Question

Find the value of k 2x+3y=7,(k+1)x+(2k-1)y=4k+1

Answer 1

Explanation:

hey mate .......

the solution can obtain by cross multiplication method

2x+3y-7=0

(k+1)x+(2k-1)y-(4k+1)=0

a1/a2= 2/(k+1)

b1/b2= 3/(2k-1)

c1/c2= -7/-(4k+1) = 7/(4k+1)

minus cancelled

a1/a2=b1/b2

2/(k+1)=3/(2k-1)

crossed multiply them we get

2(2k-1)=3(k+1)

4k-2=3k+3

4k-3k=3+2

k=5

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