find the value of k. 2x + 5 y = 9 and 4x + (k+1)y = 18
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Answered by
1
Answer:
[2x +5y = 9] ×4
[4x+ (k+1)y = 18] ×2
8x +20y =36
8x +2(k+1)y =36
– – –
20y-2(k+1)y =0
2y[10-(k+1)] =0
-(k+1) = -10
k+1 =10
k = 9
Answered by
2
Answer:
2x+5y=9......1st eq and 4x+(k+1)y=18......2eq subtract 1st eq from 2nd eq then we get 2x+(k+1)y-5y=9....3rd eq from 1st eq we get 2x=9-5y.... 4th eq substitute 4th eq in 3rd eq we get the final answer that is k=9
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