Find the value of K :(3/11)k+8 ÷ (3/11)⁴ = (3/11) ²k
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Answer:
Correct option is
A
4
Let A≡
x
1
y
1
(−3,11)
, B≡
x
2
y
2
(6,2)
and C≡
x
3
y
3
(K,4)
.
Slope of line AB= Slope of line BC
x
2
−x
1
y
2
−y
1
=
x
3
−x
2
y
3
−y
2
6+3
2−11
=
K−6
4−2
⇒
9
−9
=
K−6
2
⇒−1(K−6)=2
⇒−K+6=2
⇒−K=2−6
⇒−K=−4
⇒K=4
Step-by-step explanation:
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