Math, asked by tirumalasangadi, 17 days ago

Find the value of k(= 3x²-k√3x-k)​

Answers

Answered by sreepoojitha31977
0

Answer:

a=3, b=-k√3, c=-k

if the roots are real

b²-4ac>0

(-k√3)²-4(3)(-k)>0

3k²+12k>0

3k(k+4)>0

k>-4

if the roots are equal and real

b²-4ac=0

(k√3)²-4(3)(-k)=0

3k²+12k=0

3k(k+4)=0

k=-4

if the roots are not real

b²-4ac<0

(k√3)²-4(3)(-k)<0

3k²+12k<0

3k(k+4)<0

k<-4

Similar questions