Math, asked by bhushanbarde19744, 2 months ago

Find the value of k

-(4/5)²×(4/5)⁵=(4/5)6k+1​

Answers

Answered by rohantarafdar
16

Answer:

\frac{-31503}{125000}

Step-by-step explanation:

    -(4/5)²×(4/5)⁵= (4/5)6k+1​

⇒-(4/5)⁵⁺²= (4/5)6k+1​

⇒-(4/5)⁷ = (4/5)6k+1

⇒(4/5)6k+1 = -(4/5)⁷

⇒(4/5)6k+1 = -(16384/78125)

⇒(4/5)6k = -(16384/78125)-1

⇒(4/5)6k = \frac{-16384-78125}{78125}

⇒(4/5)6k = \frac{-94509\\}{78125}

⇒6k = \frac{-94509\\}{78125} ×\frac{5}{4}

⇒k =  \frac{-94509\\}{78125}×\frac{5}{4}×\frac{1}{6}

∴k = \frac{-31503}{125000}

Answered by srinigowda1954
0

Answer:

−31503

Step-by-step explanation:

-(4/5)²×(4/5)⁵= (4/5)6k+1

⇒-(4/5)⁵⁺²= (4/5)6k+1

⇒-(4/5)⁷ = (4/5)6k+1

⇒(4/5)6k+1 = -(4/5)⁷

⇒(4/5)6k+1 = -(16384/78125)

⇒(4/5)6k = -(16384/78125)-1

⇒(4/5)6k = \frac{-16384-78125}{78125}

78125

−16384−78125

⇒(4/5)6k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

⇒6k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

×\frac{5}{4}

4

5

⇒k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

×\frac{5}{4}

4

5

×\frac{1}{6}

6

1

∴k = \frac{-31503}{125000}

125000−31503

Step-by-step explanation:

-(4/5)²×(4/5)⁵= (4/5)6k+1

⇒-(4/5)⁵⁺²= (4/5)6k+1

⇒-(4/5)⁷ = (4/5)6k+1

⇒(4/5)6k+1 = -(4/5)⁷

⇒(4/5)6k+1 = -(16384/78125)

⇒(4/5)6k = -(16384/78125)-1

⇒(4/5)6k = \frac{-16384-78125}{78125}

78125

−16384−78125

⇒(4/5)6k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

⇒6k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

×\frac{5}{4}

4

5

⇒k = \begin{gathered}\frac{-94509\\}{78125}\end{gathered}

78125

−94509

×\frac{5}{4}

4

5

×\frac{1}{6}

6

1

∴k = \frac{-31503}{125000}

125000

−31503

−31503

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