Find the value of k, -4 is a zero of P(x)=xsquare-x-2k-2(2)
Answers
Answered by
4
Hey
Here is your answer,
If x = -4 , substitute the value of x,
X^2 - x - 2k - 2(2) =0
(-4)^2 - (-4) - 2k - 4=0
16 - 2k = 0
-2k = -16
k = 16/2
k = 8
Hope it helps you!
Here is your answer,
If x = -4 , substitute the value of x,
X^2 - x - 2k - 2(2) =0
(-4)^2 - (-4) - 2k - 4=0
16 - 2k = 0
-2k = -16
k = 16/2
k = 8
Hope it helps you!
Answered by
22
Hello dear friend .
____________________________
● Solution - { hope this helps you }
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Given x = - 4
is one zero of the Polynomial x^2 - x - 2k - 2(2)
THEREFORE , it will satisfy the above Polynomial .
Now , we have
=> (-4)^2 - ( -4)- 2k - 4 = 0
=> 16 + 4 - 2k - 4 = 0
=> 20 - 2k - 4 = 0
=> - 16 + 2k = 0
=> 2k = 0 + 16
=> 2k = 16
=> k = 16 / 2 = 8
=> k = 8
So , the value of k is 8 .
________________________________
☺☺☺
____________________________
● Solution - { hope this helps you }
--------------------------------------------------
Given x = - 4
is one zero of the Polynomial x^2 - x - 2k - 2(2)
THEREFORE , it will satisfy the above Polynomial .
Now , we have
=> (-4)^2 - ( -4)- 2k - 4 = 0
=> 16 + 4 - 2k - 4 = 0
=> 20 - 2k - 4 = 0
=> - 16 + 2k = 0
=> 2k = 0 + 16
=> 2k = 16
=> k = 16 / 2 = 8
=> k = 8
So , the value of k is 8 .
________________________________
☺☺☺
Elisha15:
mark one Answer as brainlist plzz
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