Math, asked by govindaj3, 1 year ago

Find the value of k, -4 is a zero of P(x)=xsquare-x-2k-2(2)

Answers

Answered by sijasubbiah
4
Hey

Here is your answer,

If x = -4 , substitute the value of x,

X^2 - x - 2k - 2(2) =0
(-4)^2 - (-4) - 2k - 4=0
16 - 2k = 0
-2k = -16
k = 16/2
k = 8

Hope it helps you!
Answered by Elisha15
22
Hello dear friend .
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● Solution - { hope this helps you }

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Given x = - 4
is one zero of the Polynomial x^2 - x - 2k - 2(2)

THEREFORE , it will satisfy the above Polynomial .
Now , we have

=> (-4)^2 - ( -4)- 2k - 4 = 0

=> 16 + 4 - 2k - 4 = 0

=> 20 - 2k - 4 = 0

=> - 16 + 2k = 0

=> 2k = 0 + 16

=> 2k = 16

=> k = 16 / 2 = 8

=> k = 8

So , the value of k is 8 .

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Elisha15: mark one Answer as brainlist plzz
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