Math, asked by vinayak110, 1 year ago

find the value of k(-4) is a zero of polynomial x^2-x-(2k+2)

Answers

Answered by KDPatak
1

Answer:

To find the value of k so that negative for becomes a root of this polynomial.

x^2 -x- (2K -2)

First simplify the given polynomial.

=> x^2 - x -2k +2

Second, substitute the value (- 4) in place of x

» (-4)^2 - (-4) -2K +2 =0

» 16 + 4 + 2 -2K = 0

» 22 -2k = 0

» -2K = -22

» k = 11

Thanks for the value of k = 11 negative for will be the root of the polynomial.

Answered by Anonymous
1

Step-by-step explanation:

question:

if -4 is a zero of polynomial x²-x-(2+2k) find value of k

Answer:

-4 is zero of x²-x-(2+2k)

value of k =>

p(-4)=> (-4)²-(-4)-(2+2k)=0

=> 20= 2 + 2k

k = 9

ans= 9

hope this helps you

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