Question

find the value of K, (-4) is a zero of the
p(x) =
$x ^{2} - x - ( 2k + 2)$
​

Answer 1

Step-by-step explanation:

substituting x=-4 in the given equation

(-4)(-4)-(-4)-(2k+2)=0

I have squared -4

16-(-4)+(2k+2)=0

16+4+2k+2=0

20+2+2k=0

22+2k=0

2k=-22

k=-22/2

k=-11

if you want to check the answer substitute x=-4 and k=-11