find the value of k, (-4) is the zero of the polynomial x^2 - x-(2k+2)
Answers
Answered by
18
let p(x)=x²-x-(2k+2),
if -4 is the zero of p(x) then
p(-4)=0,
(-4)²-(-4)-(2k+2)=0,
16+4-2(k+1)=0,
20-2(k+1)=0,
2(k+1)=20,
k+1=10,
k=9
if -4 is the zero of p(x) then
p(-4)=0,
(-4)²-(-4)-(2k+2)=0,
16+4-2(k+1)=0,
20-2(k+1)=0,
2(k+1)=20,
k+1=10,
k=9
Answered by
4
this your answer mate hope it helps u
Attachments:
anureet12:
i think it's wrong❌
Similar questions