Math, asked by dasjunupehoye, 10 months ago

find the value of k
@ 22-(K + 4)x+2K+5=0
© 2re + gie-K®=0
© (K-3/1² + 6x +9=0
D (K-2) u 2 + 2 kr +2=0

Answers

Answered by parthbole02

2

Answer:

K=k because k=k as k=k therefore k=k

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