Question

find the value of K by deletion method first equation Kx + 2y = 5 second equation 3x + y = 1​

Answer 1

Answer:

k=6

Step-by-step explanation:

kx+2y=5…(1)

3x+y=1 …(2)

First multiply the second equation by 2

We get:

6x+2y=2

Now subtracting (2) from (1), we get:

kx+2y−6x−2y=5−2

(k−6)x=3

x=

k−6

3

So, here if we put any value of k, then we will get a corresponding value of x but if we put k=6, then we will not get any value of x

So, for k=6 this equation has no solution.

Answer 2

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$\mathbf\pink{ answer }$

The given system of equation may be written as

kx + 2y - 5 = 0

3x + y - 1 = 0

It is of the form

a₁x + b₁y+c₁ = 0

a2x + b₂y + c₂ = 0

Where a1 =k, b₁ = 2, C₁ = −5And a2 = 3, b2 = 1, C₂ = −1

Where, a1

k, b₁ = 2, C₁

And a2 = 3, b2 = 1, C₂ = −1

1) The given system will have a unique solution, if

a1 a2 b₁ b2

# 1 介

⇒k‡ 6

So, the given system of equations will have a unique solution, if k ‡ 6