Question

Find the value of k each of the following 3x2-kx-2=0; x=2

Answer 1

Given

X= 2

so,

3×(2)^2-k(2)-2=0

3×4-2k-2=0

12-2k-2=0

10-2k=0

-2k= (-10)

2k=10

k= 10/2

k = 5

[ANSWER K = 5]

I hope it helps

thank you

tc(♥ó㉨ò)ﾉ♡

Answer 2

$p(x) = {3x}^{2} - kx - 2 = 0 \\ x = 2 \\ p(2) = 3 {(2)}^{2} - k(2) - 2 = 0 \\ 3(4) - 2k - 2 = 0 \\ 12 - 2k - 2 = 0 \\ 10 - 2k = 0 \\ 10 = 2k \\ 2k = 10 \\ k = \frac{10}{2} \\ k = 5$