Question

find the value of k each of the following quadratic equation so that they have equal roots kx(x-2)+6=0

Answer 1

For an equation ax^2 + bx +c =0

The nature of roots are determined by b^2 - 4ac

if b^2 - 4ac = 0 - real , equal roots

kx(x-2)+6 =0

kx^2 -2kx + 6 =0

here a = k, b = -2k ,c =6

b^2 - 4ac

= (-2k)^2 - 4*k*6

= 4k^2 - 24k

For it to have equal roots

4k^2 - 24k =0

4k(k -6)=0

so k = 0 ,6

k = 0 will not satisfy

Therefore answer is k = 6

Answer 2

Answer:

I hope it is helpful..................

be happy

keep smiling

enjoy your life ...................