Question

Find the value of k equation having real
Root Kx (x-2)+6=0

Answer 1

Answer:

the given equation can be written in the form of

k {x}^{2} - 2kx + 6 = 0kx

2

−2kx+6=0

now it has equal roots that means The Discriminant is 0

D = 0

Also

\begin{gathered} {b}^{2} - 4ac = 0 \\ {4k}^{2} - 4(k)(6) = 0 \\ 4 {k}^{2} - 24k = 0 \\ 4k(k - 6) = 0 \\ k - 6 = 0 \\ k = 6 \end{gathered}

b

2

−4ac=0

4k

2

−4(k)(6)=0

4k

2

−24k=0

4k(k−6)=0

k−6=0

k=6

Hence the value of K is 6.