find the value of k following equation have infinite solution 2x+3y=7(k-1)x +(k+2)y=3k
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By Useing the formal of cross multiplication
2/K-1=3/K+2=-7/-3K
2×(k+2)=3×(k-1)
2k+4=3K-3
2K-3K=-3-4
-K=-7
K=7
2/K-1=3/K+2=-7/-3K
2×(k+2)=3×(k-1)
2k+4=3K-3
2K-3K=-3-4
-K=-7
K=7
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