Find the value of k for 2x^2-kx+3=0 so that it has 2 equal roots
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Answer:
k = ± 4√3
Step-by-step explanation:
Q.E = 2x² - kx + 3
a = 2 , b = -k , c = 3
If the Q.E has two equal roots then D should be equal to 0.
⇒ b² - 4ac = 0
⇒ (-k)² - 4(2)(3) = 0
⇒ k² - 48 = 0
⇒ k² = 48
⇒ k = √48 = √(16 × 3) = ±4√3
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