Question

Find the value of k for 2x^2-kx+3=0 so that it has 2 equal roots

Answer 1

Answer:

k = ± 4√3

Step-by-step explanation:

Q.E = 2x² - kx + 3

a = 2 , b = -k , c = 3

If the Q.E has two equal roots then D should be equal to 0.

⇒ b² - 4ac = 0

⇒ (-k)² - 4(2)(3) = 0

⇒ k² - 48 = 0

⇒ k² = 48

⇒ k = √48 = √(16 × 3) =  ±4√3