Find the value of k for 2x + 5y=0, kx+10y=0 has non zero solution. PLz fast tommorow is my fa
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Answered by
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Solution :-
2x + 5y = 0
⇒ 2x = - 5y ..............(1)
kx + 10y = 0
⇒ kx = - 10y .............(2)
From (1) and (2)
⇒ 2x/kx = (- 5y)/(- 10y)
⇒ 2/k = 5y/10y
⇒ 2/k = 1/2
⇒ k*1 = 2*2
⇒ k = 4
So, the value of k is 4.
Answer.
2x + 5y = 0
⇒ 2x = - 5y ..............(1)
kx + 10y = 0
⇒ kx = - 10y .............(2)
From (1) and (2)
⇒ 2x/kx = (- 5y)/(- 10y)
⇒ 2/k = 5y/10y
⇒ 2/k = 1/2
⇒ k*1 = 2*2
⇒ k = 4
So, the value of k is 4.
Answer.
Answered by
0
Answer:
k=4
Step-by-step explaination:
2x + 5y = 0
⇒ 2x = - 5y ..............(1)
kx + 10y = 0
⇒ kx = - 10y .............(2)
From (1) and (2)
⇒ 2x/kx = (- 5y)/(- 10y)
⇒ 2/k = 5y/10y
⇒ 2/k = 1/2
⇒ k= 2*2
⇒ k = 4
So, the value of k is 4.
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