find the value of k for 3x^2-2kx+m=0 when x=2,m=3
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3(2)^2 - 2k(2)+3=0 ,,,, 12-4k+3=0 k = 15/4
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Solution==>>
Given => x=2 and m=3 or p(x)=3x²-2kx+m=0
To find=> value of k
Solution=> substitute the value of x and m in p(x)
3(2)²-2k(2)+3=0
3(4)-4k+3=0
12-4k+3=0
-4k=-12-3
-4k=-15
k=15/4
•.• value of k is 15/4
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