Math, asked by mahimaaa200375, 1 year ago

find the value of k for 3x^2-2kx+m=0 when x=2,m=3​

Answers

Answered by chemistrywala
3

3(2)^2 - 2k(2)+3=0 ,,,, 12-4k+3=0 k = 15/4

Answered by harjotsinghbhinder13
2

Solution==>>

Given => x=2 and m=3 or p(x)=3x²-2kx+m=0

To find=> value of k

Solution=> substitute the value of x and m in p(x)

3(2)²-2k(2)+3=0

3(4)-4k+3=0

12-4k+3=0

-4k=-12-3

-4k=-15

k=15/4

•.• value of k is 15/4

Answer...

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