Math, asked by pawriyabillu, 7 months ago

find the value of k for each of the following equations if x =1 , y =1is its solution 1 . x-y=k. 2. 5x+2ky=3k . 3. 9kx+7ky=48​

Answers

Answered by av1266108
4

Answer:

We have given x = 1 and y =1

the equation is,

                       5x + 2ky = 3k                              

                       5 × 1 + 2 × k ×1 = 3k

                        5 + 2k = 3k

                          5 = 3k - 2k

                           5 = k

so the value of k is 5

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Answered by Anonymous
5

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Question :-

find the value of k for each of the following equations if x =1 , y =1 is its solution 1 . x-y=k. 2. 5x+2ky=3k . 3. 9kx+7ky=48

Step by step solution :-

1.x - y = k

x = 1

y = 1

x - y = k

1 - 1 = k

k = 0

2. 5x + 2ky = 3k

x = 1

y = 1

5*1 + 2* k * 1 = 3

5 + 2k = 3k

5 = 3k - 2k

k = 5

3. 9kx + 7ky = 48x

x = 1

y = 1

9 * k * 1 + 7 * k* 1 = 48 *1

9k + 7k = 48

16k = 48

k = 48 /12

k = 4

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