Question

Find the value of k for each of the following quadratic equation so that the equal roots for X square + kx + 9 = 0

Answer 1

Answer:

hey frnd here is your answer

Step-by-step explanation:

your equation is x²+Kx+9.

For Having Equal roots D=0 where D=b²-4ac.

so here D=0

b²-4ac=0

b²=4ac

we have b=k ,a=1 c=9

k²=4(1)(9)

k²=36

k=+6, -6.

So your final answer is K=±6.

I hope you get your answer

thnx for asking

plzz mark as brainlist...

Answer 2

Solution :

$\bf{\red{\underline{\bf{Given\::}}}}$

The roots of the quadratic equation x² + kx + 9 = 0 will have equal roots.

$\bf{\red{\underline{\bf{To\:find\::}}}}$

The value of k.

$\bf{\red{\underline{\bf{Explanation\::}}}}$

We have x² + kx + 9 = 0

A/q

Discriminate (D) = 0

• a = 1

• b = k

• c = 9

Formula use :

$\boxed{\bf{b^{2} -4ac=0}}}}$

$\longrightarrow\sf{b^{2} -4ac=0}\\\\\longrightarrow\sf{(k)^{2} -4*1*9=0}\\\\\longrightarrow\sf{(k)^{2} -36=0}\\\\\longrightarrow\sf{(k)^{2} =36}\\\\\longrightarrow\sf{k=\pm\sqrt{36} }\\\\\longrightarrow\sf{\green{k=\pm\:6}}$

Thus;

The value of k is ±6 .