Question

find the value of k for each of the following quadratic equation so that the equal roots for X square + kx + 9 is equal to zero

Answer 1

Answer:

k= +6 or -6.

Step-by-step explanation:

x^2+ kx+9=0

If roots are equal, discriminent delta =0

b^2-4ac=0, where a=1, b=k, c=9

k^2-4(1)(9)=0

k^2-(4×9)=0

k^2-36=0

k^2=36

k=√36

k=+6 or -6

HOPE THIS BRING A SMILE IN YOUR FACE

Answer 2

Given :-

• Quadratic equation: x² + kx + 9 has equal roots.

To find :-

• Value of k

Solution :-

As the given quadratic equation x² + kx + 9 has equal zeros so, discriminate = 0

We will use discriminate formula :

⇒ D = b² - 4ac = 0

Comparing the given equation with ax² + bx + c we get,

• b = k
• a = 1
• c = 9

Putting values :

⇒ (k)² - (4 × 1 × 9) = 0

⇒ k² - 36 = 0

⇒ k² = 36

[ Squaring root on both sides ]

⇒ √k² = √36

⇒ k = ±6

Therefore,

∴ Hence, value of k = ±6 for which the given equation has equal roots.