Question

Find the value of k for each of the following quadratic equations ,so that they have two equal root 2×2+kx+3=0

Answer 1

Answer:

k= root 28

Step-by-step explanation:

Equation= 2*2+kx+3

=4+kx+3

=7+kx

if it has equal roots then d=0

d=b^2 - 4ac

0=k^2- 4 (1)(7)

0=k^2-28

28=k^2

k=root 28

Answer 2

Here Is Your Answer Mate.....;

2x^2 + kx + 3 = 0

Comparing the given equation with ax^2 + bx + c = 0, we get,

a = 2, b = k and c = 3

As we know, Discriminant = b^2 – 4ac

= (k)^2 – 4(2) (3)

= k2 – 24

For equal roots, we know,

Discriminant = 0

k^2 – 24 = 0

k^2 = 24

k = ±√24 = ±2√6

Hope it's Helpful....:)