Question

Find the Value of k for each of the following Quadratic Equation, so that they have two equal root
2×x^2 kx + 3 = 0.​

Answer 1

Step-by-step explanation:

$2 {x}^{2} + 2kx + 3 = 0$

The roots are real and equal.

Discriminant =0.

${b}^{2} - 4ac = 0$

$( {2k)}^{2} - 4 \times 2 \times 3 = 0$

$4 {k}^{2} - 24 = 0$

$4 {k}^{2} = 24$

${k}^{2} = \frac{24}{4}$

${k}^{2} = 6$

$k = \sqrt{6}$

The value of k are +√6 and -√6.

Answer 2

Answer:

k²-24=0

k=2√6

Step-by-step explanation:

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