Question

find the value of k for each of the following quadratic equations,so that they have two equal roots kx(x-2)+6=0​

Answer 1

Step-by-step explanation:

kx(x-2) +6=0.

kx^2-2kx+6=0 a=k, b=-2k, c=6

roots are equal b^2=4ac

(-2k)^2=4*(-2k)*6

4k^2-24k=0

4k(k-6)=0

4k=0 or k-6=0

k=0 or k=6