find the value of k for each of the following qudratic equation ,so that they have equal roots 1} x²+k(2x+k-1)=o
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1
Answer:
b^2= 4ac , if it have bottj roots equal
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for equal roots D should be equal to 0
D=b^2-4ac=0
equation is: x^2+2xk+k^2-k=0
so, b^2-4ac=0
4k^2-4(k^2-k)=0
4k^2-4k^2+4k=0
4k=0
k=0
D=b^2-4ac=0
equation is: x^2+2xk+k^2-k=0
so, b^2-4ac=0
4k^2-4(k^2-k)=0
4k^2-4k^2+4k=0
4k=0
k=0
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