Question

Find the value of k for equal roots in quadratic equation x2-2x(1+3k)-7(3+2k)=0
plz send me the answer as soon as possible
plzz i have exams tomorrow plzzz
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Answer 1

Step-by-step explanation:

Ⓗ︎Ⓘ︎Ⓘ︎ Ⓟ︎Ⓛ︎Ⓔ︎Ⓐ︎Ⓢ︎Ⓔ︎ Ⓜ︎Ⓐ︎Ⓡ︎Ⓚ︎ Ⓜ︎Ⓔ︎ Ⓐ︎Ⓢ︎ Ⓑ︎Ⓡ︎Ⓐ︎Ⓘ︎Ⓝ︎Ⓛ︎Ⓘ︎Ⓔ︎Ⓢ︎Ⓣ︎ Ⓝ︎Ⓞ︎Ⓦ︎

Ⓐ︎Ⓝ︎Ⓓ︎ DON'T FORGET TO FOLLOW HERE

Answer 2

Answer:

Step-by-step explanation: Given x2  −2x(1+3k)+7(3+2k)=0 has equal roots

we know that

For the quadratic equation to have equal roots discriminant should be zero

⟹(−2(1+3k))  02

−4(1)(7(3+2k))=0

⟹4(1+3k)  2  −28(3+2k)=0

⟹(9k  2  +6k+1)−21−14k=0

⟹9k  2  −8k−20=0

⟹9k  2  −18k+10k−20=0

⟹9k(k−2)+10(k−2)=0

⟹(9k+10)(k−2)=0

⟹k=−  10/9 ,2