Math, asked by aryanabhishek7, 1 year ago

find the value of k for equal roots in quadratic equation x2-2x(1+3k)+7(3+2k)=0

Answers

Answered by aravind74
8
given,
x^2-2x(1+3k)+7(3+2k)=0
x^2-2x-6kx+21+14k=0
x^2-6kx+12x+21=0
x^2+6kx+21=0
here a=1,b=6k,c=21
b^2-4ac=0
(6k)^2-4(1)(21)=0
36k^2-84=0
36k^2=84
k^2=84/36
k^2=21/18
k=√21/18
or
k=√21/√18
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