Math, asked by hsabhani09123, 8 months ago

find the value of k for following distribution where mean is 16​

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Answered by mysticd
1

\begin {tabular} {| c | c | c | c | }</p><p>\cline { 1-4 } Class &amp; f_{1} &amp; x_{i} &amp; f_{i}x_{i} \\</p><p>\cline { 1-4 } 10 -12 &amp; 12 &amp; 11 &amp; 132 \\</p><p>\cline { 1-4} 12-14 &amp; 16 &amp; 13 &amp; 208 \\</p><p>\cline {1-4} 14-16 &amp; 20 &amp; 15 &amp; 300 \\</p><p>\cline { 1-4 } 16-18 &amp; 24 &amp; 17 &amp; 408 \\</p><p>\cline { 1-4 } 18-20 &amp; k &amp; 19 &amp; 19k \\</p><p>\cline { 1-4 } 20-22 &amp; 8 &amp; 21 &amp; 168 \\</p><p>\cline { 1-4 } 22 - 24 &amp;4 &amp; 23 &amp; 92 \\</p><p>\cline { 1-4 } &amp; \Sigma f_{i} = 84+k &amp; \_&amp; \Sigma f_{i}x_{i} = 360 + k \\</p><p></p><p>\cline {1-4} \end { tabular}

 \overline {x} = 16\: (given)

\implies  \frac{\Sigma f_{i}x_{i}}{\Sigma f_{i} } = 16

 \implies \frac{1308 + 19k }{84+k} = 16

 \implies 1308 + 19k = 16(84+k)

 \implies 19k - 16k = 1344 - 1308

 \implies 3k = 36

 \implies k = 12

Therefore.,

 \red { Value \:of \: k } \green { = 12 }

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