Question

Find the value of k for k2 x2 – 2 (2 k - 1) x + 4 = 0, so that it has two equal roots.
plz

ans its important

Answer 1

Step-by-step explanation:

k^2 x^2 - 2(2k-1)x + 4

where a = k^2, b = -2(2k - 1) and c = 4

therefore, the discriminant

D = b^2 - 4ac

= (-2(2k - 1))^2 - 4 x (k^2) x (4)

= 4(2k - 1)^2 - 16k^2

= 4(4k^2 + 1 - 4k) - 16k^2

= 16k^2 + 4 - 16k - 16k^2

= 4 - 16k

∵ Roots of the given equation are real and equal

∴ D = 0

⇒ 4 - 16k = 0

⇒ -16k = -4

=> 16k =4

=> k = 4/16

=> k = 1/4 ans