Question

find the value of k for kx+ 3y=k-3, 12x +ky=k which has infinity many solutions


please give me the correct answer not. wrong​

Answer 1

Answer:

a1=k b1=3 c1 =k-3

a2=12 b2=k c2=k

according to question

$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$

$\frac{k}{12} = \frac{3}{k} = \frac{k - 3}{k}$

$k {}^{2} = 36 \\ k = +6or - 6$

therefore if k = 6

$\frac{6}{12} = \frac{3}{6} \\ \frac{1}{2} = \frac{1}{2}$

therefore k = +6