Find the value of k for quadratic equation 2x^2-x+k=0, so that they hace two equal roots
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Answered by
54
We know that, when the roots are equal,discriminant is zero.
∆=0 or b²-4ac=0
Given 2x²-x+k=0
a=2,b=-1,c=k
(-1)²-4*2*k=0
1-8k=0
8k=1
k=1/8
the value of k for quadratic equation 2x^2-x+k=0, so that they have two equal roots is 1/8
∆=0 or b²-4ac=0
Given 2x²-x+k=0
a=2,b=-1,c=k
(-1)²-4*2*k=0
1-8k=0
8k=1
k=1/8
the value of k for quadratic equation 2x^2-x+k=0, so that they have two equal roots is 1/8
Answered by
28
b²-4ac=0
b=-1
a=2
c=k
therefore,
(-1)²-4(2)(k)=0
1-8k=0
8k=1
k=1/8
b=-1
a=2
c=k
therefore,
(-1)²-4(2)(k)=0
1-8k=0
8k=1
k=1/8
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